Virgin, Utah
Virgin is a town located in
Washington County, Utah. As of the
2000 census, the town had a total population of 394.
Geography
\nVirgin is located at 37°12'6" North, 113°11'23" West (37.201620, -113.189617)1.
According to the
United States Census Bureau, the town has a total area of 30.9
km² (11.9
mi²). 30.9 km² (11.9 mi²) of it is land and none of the area is covered with water.
Demographics
\nAs of the census of
2000, there are 394 people, 146 households, and 102 families residing in the town. The
population density is 12.8/km² (33.1/mi²). There are 170 housing units at an average density of 5.5/km² (14.3/mi²). The racial makeup of the town is 96.45% White, 0.00%
African American, 0.51%
Native American, 0.00%
Asian, 1.27% Pacific Islander, 0.00% from other races, and 1.78% from two or more races. 1.27% of the population are
Hispanic or
Latino of any race.
There are 146 households out of which 30.8% have children under the age of 18 living with them, 58.2% are married couples living together, 8.2% have a female householder with no husband present, and 30.1% are non-families. 24.0% of all households are made up of individuals and 7.5% have someone living alone who is 65 years of age or older. The average household size is 2.70 and the average family size is 3.23.
In the town the population is spread out with 26.1% under the age of 18, 11.4% from 18 to 24, 25.1% from 25 to 44, 23.4% from 45 to 64, and 14.0% who are 65 years of age or older. The median age is 37 years. For every 100 females there are 114.1 males. For every 100 females age 18 and over, there are 109.4 males.
The median income for a household in the town is $36,953, and the median income for a family is $37,500. Males have a median income of $32,625 versus $19,500 for females. The per capita income for the town is $14,797. 9.0% of the population and 9.3% of families are below the poverty line. Out of the total people living in poverty, 7.4% are under the age of 18 and 0.0% are 65 or older.