is a town located in Pierce County, Washington
. As of the 2000
census, the town had a total population of 21,588.
Geography\nSpanaway is located at 47°5'52" North, 122°25'26" West (47.097887, -122.424016)1
According to the United States Census Bureau
, the town has a total area of 22.5 km²
). 21.6 km² (8.3 mi²) of it is land and 1.0 km² (0.4 mi²) of it is water. The total area is 4.25% water.
Demographics\nAs of the census
, there are 21,588 people, 7,659 households, and 5,820 families residing in the town. The population density
is 1,000.6/km² (2,592.0/mi²). There are 7,963 housing units at an average density of 369.1/km² (956.1/mi²). The racial makeup of the town is 71.13% White, 9.11% African American
, 1.61% Native American
, 6.34% Asian
, 2.12% Pacific Islander, 2.15% from other races, and 7.55% from two or more races. 5.49% of the population are Hispanic
of any race.
There are 7,659 households out of which 40.4% have children under the age of 18 living with them, 57.1% are married couples living together, 13.6% have a female householder with no husband present, and 24.0% are non-families. 18.2% of all households are made up of individuals and 4.8% have someone living alone who is 65 years of age or older. The average household size is 2.82 and the average family size is 3.17.
In the town the population is spread out with 30.0% under the age of 18, 8.4% from 18 to 24, 32.7% from 25 to 44, 21.5% from 45 to 64, and 7.3% who are 65 years of age or older. The median age is 33 years. For every 100 females there are 99.3 males. For every 100 females age 18 and over, there are 96.2 males.
The median income for a household in the town is $46,210, and the median income for a family is $50,076. Males have a median income of $35,525 versus $26,758 for females. The per capita income for the town is $17,928. 10.8% of the population and 7.8% of families are below the poverty line. Out of the total people living in poverty, 15.5% are under the age of 18 and 7.3% are 65 or older.