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Sandusky, Michigan

Sandusky is a city located in Sanilac County, Michigan. As of the 2000 census, the city had a total population of 2,745. It is the county seat of Sanilac County6.


\nAccording to the
United States Census Bureau, the city has a total area of 4.9 km² (1.9 mi²). 4.9 km² (1.9 mi²) of it is land and none of it is covered by water.


\nAs of the
census of 2000, there are 2,745 people, 1,081 households, and 649 families residing in the city. The population density is 557.8/km² (1,446.3/mi²). There are 1,168 housing units at an average density of 237.4/km² (615.4/mi²). The racial makeup of the city is 95.12% White, 0.87% African American, 0.15% Native American, 1.75% Asian, 0.00% Pacific Islander, 1.35% from other races, and 0.77% from two or more races. 3.42% of the population are Hispanic or Latino of any race. There are 1,081 households out of which 31.2% have children under the age of 18 living with them, 43.6% are married couples living together, 13.0% have a female householder with no husband present, and 39.9% are non-families. 35.9% of all households are made up of individuals and 16.7% have someone living alone who is 65 years of age or older. The average household size is 2.32 and the average family size is 2.97. In the city the population is spread out with 22.8% under the age of 18, 9.3% from 18 to 24, 29.5% from 25 to 44, 19.6% from 45 to 64, and 18.8% who are 65 years of age or older. The median age is 38 years. For every 100 females there are 86.5 males. For every 100 females age 18 and over, there are 85.8 males. The median income for a household in the city is $33,667, and the median income for a family is $44,622. Males have a median income of $31,531 versus $20,932 for females. The per capita income for the city is $17,639. 11.0% of the population and 7.2% of families are below the poverty line. Out of the total people living in poverty, 8.9% are under the age of 18 and 14.0% are 65 or older.