Republican City, NebraskaRepublican City
is a village located in Harlan County, Nebraska
. As of the 2000
census, the village had a total population of 209.
Geography\nRepublican City is located at 40°5'52" North, 99°13'17" West (40.097708, -99.221301)1
According to the United States Census Bureau
, the village has a total area of 0.9 km²
). 0.9 km² (0.3 mi²) of it is land and none of it is covered by water.
Demographics\nAs of the census
, there are 209 people, 107 households, and 69 families residing in the village. The population density
is 244.5/km² (633.8/mi²). There are 218 housing units at an average density of 255.1/km² (661.1/mi²). The racial makeup of the village is 99.52% White, 0.00% African American
, 0.00% Native American
, 0.00% Asian
, 0.00% Pacific Islander, 0.00% from other races, and 0.48% from two or more races. 0.96% of the population are Hispanic
of any race.
There are 107 households out of which 15.0% have children under the age of 18 living with them, 57.9% are married couples living together, 4.7% have a female householder with no husband present, and 35.5% are non-families. 33.6% of all households are made up of individuals and 20.6% have someone living alone who is 65 years of age or older. The average household size is 1.95 and the average family size is 2.43.
In the village the population is spread out with 12.9% under the age of 18, 5.7% from 18 to 24, 11.0% from 25 to 44, 34.0% from 45 to 64, and 36.4% who are 65 years of age or older. The median age is 60 years. For every 100 females there are 101.0 males. For every 100 females age 18 and over, there are 100.0 males.
The median income for a household in the village is $26,250, and the median income for a family is $32,500. Males have a median income of $27,500 versus $17,917 for females. The per capita income for the village is $14,863. 8.5% of the population and 6.9% of families are below the poverty line. Out of the total people living in poverty, 10.5% are under the age of 18 and 12.2% are 65 or older.