is a town located in Benton County, Indiana
. As of the 2000
census, the town had a total population of 1,312.
Geography\nOtterbein is located at 40°29'20" North, 87°5'43" West (40.488919, -87.095355)1
According to the United States Census Bureau
, the town has a total area of 1.5 km²
). 1.5 km² (0.6 mi²) of it is land and none of it is covered by water.
Demographics\nAs of the census
, there are 1,312 people, 498 households, and 359 families residing in the town. The population density
is 888.7/km² (2,291.9/mi²). There are 518 housing units at an average density of 350.9/km² (904.9/mi²). The racial makeup of the town is 98.02% White, 0.23% African American
, 0.23% Native American
, 0.00% Asian
, 0.00% Pacific Islander, 0.61% from other races, and 0.91% from two or more races. 1.07% of the population are Hispanic
of any race.
There are 498 households out of which 42.4% have children under the age of 18 living with them, 54.2% are married couples living together, 12.2% have a female householder with no husband present, and 27.9% are non-families. 24.5% of all households are made up of individuals and 11.8% have someone living alone who is 65 years of age or older. The average household size is 2.63 and the average family size is 3.11.
In the town the population is spread out with 30.8% under the age of 18, 8.8% from 18 to 24, 31.6% from 25 to 44, 17.1% from 45 to 64, and 11.6% who are 65 years of age or older. The median age is 32 years. For every 100 females there are 96.1 males. For every 100 females age 18 and over, there are 86.8 males.
The median income for a household in the town is $40,524, and the median income for a family is $45,341. Males have a median income of $31,000 versus $20,944 for females. The per capita income for the town is $17,128. 6.9% of the population and 4.8% of families are below the poverty line. Out of the total people living in poverty, 6.8% are under the age of 18 and 9.9% are 65 or older.