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Mead, Nebraska

Mead is a village located in Saunders County, Nebraska. As of the 2000 census, the village had a total population of 564.


\nMead is located at 41°13'34" North, 96°29'18" West (41.226201, -96.488373)
1. According to the United States Census Bureau, the village has a total area of 0.8 km² (0.3 mi²). 0.8 km² (0.3 mi²) of it is land and none of it is covered by water.


\nAs of the
census of 2000, there are 564 people, 203 households, and 156 families residing in the village. The population density is 680.5/km² (1,758.8/mi²). There are 210 housing units at an average density of 253.4/km² (654.9/mi²). The racial makeup of the village is 98.76% White, 0.00% African American, 0.00% Native American, 0.18% Asian, 0.00% Pacific Islander, 0.18% from other races, and 0.89% from two or more races. 2.13% of the population are Hispanic or Latino of any race. There are 203 households out of which 36.5% have children under the age of 18 living with them, 64.0% are married couples living together, 8.9% have a female householder with no husband present, and 22.7% are non-families. 16.3% of all households are made up of individuals and 7.9% have someone living alone who is 65 years of age or older. The average household size is 2.78 and the average family size is 3.11. In the village the population is spread out with 28.4% under the age of 18, 9.0% from 18 to 24, 32.3% from 25 to 44, 19.3% from 45 to 64, and 11.0% who are 65 years of age or older. The median age is 34 years. For every 100 females there are 99.3 males. For every 100 females age 18 and over, there are 98.0 males. The median income for a household in the village is $51,339, and the median income for a family is $51,354. Males have a median income of $35,357 versus $21,806 for females. The per capita income for the village is $17,654. 2.7% of the population and 1.2% of families are below the poverty line. Out of the total people living in poverty, 1.1% are under the age of 18 and 4.4% are 65 or older.