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Koontz Lake, Indiana

Koontz Lake is a town located in Marshall County, Indiana. As of the 2000 census, the town had a total population of 1,554.


\nKoontz Lake is located at 41°24'50" North, 86°28'57" West (41.413804, -86.482628)
1. According to the United States Census Bureau, the town has a total area of 10.1 km² (3.9 mi²). 8.8 km² (3.4 mi²) of it is land and 1.3 km² (0.5 mi²) of it is water. The total area is 12.85% water.


\nAs of the
census of 2000, there are 1,554 people, 652 households, and 449 families residing in the town. The population density is 177.0/km² (459.1/mi²). There are 931 housing units at an average density of 106.0/km² (275.0/mi²). The racial makeup of the town is 97.75% White, 0.13% African American, 0.58% Native American, 0.00% Asian, 0.00% Pacific Islander, 0.58% from other races, and 0.97% from two or more races. 1.74% of the population are Hispanic or Latino of any race. There are 652 households out of which 26.7% have children under the age of 18 living with them, 56.6% are married couples living together, 8.4% have a female householder with no husband present, and 31.0% are non-families. 26.5% of all households are made up of individuals and 13.3% have someone living alone who is 65 years of age or older. The average household size is 2.38 and the average family size is 2.85. In the town the population is spread out with 21.6% under the age of 18, 7.7% from 18 to 24, 25.7% from 25 to 44, 27.0% from 45 to 64, and 18.0% who are 65 years of age or older. The median age is 41 years. For every 100 females there are 93.8 males. For every 100 females age 18 and over, there are 94.1 males. The median income for a household in the town is $37,137, and the median income for a family is $45,114. Males have a median income of $35,388 versus $21,563 for females. The per capita income for the town is $21,429. 7.7% of the population and 6.7% of families are below the poverty line. Out of the total people living in poverty, 11.5% are under the age of 18 and 5.7% are 65 or older.