Jefferson, South DakotaJefferson
is a city located in Union County, South Dakota
. As of the 2000
census, the city had a total population of 586.
Geography\nJefferson is located at 42°36'16" North, 96°33'46" West (42.604514, -96.562823)1
According to the United States Census Bureau
, the city has a total area of 0.8 km²
). 0.8 km² (0.3 mi²) of it is land and none of the area is covered with water.
Demographics\nAs of the census
, there are 586 people, 228 households, and 160 families residing in the city. The population density
is 780.2/km² (2,028.2/mi²). There are 240 housing units at an average density of 319.5/km² (830.7/mi²). The racial makeup of the city is 96.59% White, 0.85% African American
, 1.02% Native American
, 0.17% Asian
, 0.00% Pacific Islander, 0.00% from other races, and 1.37% from two or more races. 1.88% of the population are Hispanic
of any race.
There are 228 households out of which 38.6% have children under the age of 18 living with them, 61.4% are married couples living together, 6.6% have a female householder with no husband present, and 29.8% are non-families. 25.9% of all households are made up of individuals and 10.1% have someone living alone who is 65 years of age or older. The average household size is 2.57 and the average family size is 3.13.
In the city the population is spread out with 29.7% under the age of 18, 6.8% from 18 to 24, 30.2% from 25 to 44, 22.0% from 45 to 64, and 11.3% who are 65 years of age or older. The median age is 33 years. For every 100 females there are 103.5 males. For every 100 females age 18 and over, there are 99.0 males.
The median income for a household in the city is $47,625, and the median income for a family is $52,813. Males have a median income of $34,750 versus $23,750 for females. The per capita income for the city is $18,467. 3.7% of the population and 1.3% of families are below the poverty line. Out of the total people living in poverty, 4.0% are under the age of 18 and 3.9% are 65 or older.