is a city located in Broward County, Florida
. As of the 2000
census, the city had a total population of 34,282.
Geography\nHallandale is located at 25°59'12" North, 80°8'46" West (25.986719, -80.146024)1
According to the United States Census Bureau
, the city has a total area of 11.8 km²
). 10.9 km² (4.2 mi²) of it is land and 0.9 km² (0.3 mi²) of it is water. The total area is 7.47% water.
Demographics\nAs of the census
, there are 34,282 people, 18,051 households, and 8,700 families residing in the city. The population density
is 3,144.0/km² (8,143.1/mi²). There are 25,022 housing units at an average density of 2,294.8/km² (5,943.5/mi²). The racial makeup of the city is 77.25% White, 16.02% African American
, 0.23% Native American
, 1.00% Asian
, 0.04% Pacific Islander, 2.79% from other races, and 2.66% from two or more races. 18.81% of the population are Hispanic
of any race.
There are 18,051 households out of which 12.5% have children under the age of 18 living with them, 35.8% are married couples living together, 9.1% have a female householder with no husband present, and 51.8% are non-families. 45.2% of all households are made up of individuals and 25.8% have someone living alone who is 65 years of age or older. The average household size is 1.88 and the average family size is 2.60.
In the city the population is spread out with 13.2% under the age of 18, 5.3% from 18 to 24, 22.9% from 25 to 44, 22.8% from 45 to 64, and 35.8% who are 65 years of age or older. The median age is 53 years. For every 100 females there are 85.6 males. For every 100 females age 18 and over, there are 82.6 males.
The median income for a household in the city is $28,266, and the median income for a family is $37,171. Males have a median income of $31,287 versus $24,882 for females. The per capita income for the city is $22,464. 16.8% of the population and 13.1% of families are below the poverty line. Out of the total people living in poverty, 26.4% are under the age of 18 and 13.0% are 65 or older.