- In a projective space, two triangles are in perspective
*axially*if and only if they are in perspective*centrally*.

In an affine space nothing similar is true unless one lists various exceptions involving accidentally parallel lines. Desargues' theorem is therefore one of the most basic of simple and intuitive geometric theorems whose natural home is in projective rather than affine space.

The truth of Desargues' theorem in the plane is most readily deduced by getting it as a corollary to its truth in 3-space. Two triangles cannot be in perspective unless they fit into a space of dimension 3 or less; thus in higher dimensions the span of the two triangles is always a subspace of dimension no higher than 3.

The ten lines involved (six sides of triangles, the three lines *Aa*, *Bb*, and *Cc*, and the axis of perspectivity) and the ten points involved (the six vertices, the three points of intersection on the axis of perspectivity, and the center of perspectivity) are so arranged that each of the ten lines passes through three of the ten points, and each of the ten points lies on three of the ten lines. Those ten points and ten lines make up the **Desargues configuration**. (It is an amusing exercise to show that those incidence conditions can also be satisfied by a configuration of ten points and ten lines that is *not* incidence-isomorphic to the Desargues configuration.) The statement of the theorem above may misleadingly connote that the Desargues configuration has less symmtery than it really has: *Any* of the ten points may be chosen to be the center of perspectivity, and that choice determines which six points will be the vertices of triangles and which line will be the axis of perspecitivity.